Last updated on August 5th, 2025
We use the derivative of e^cx, which is ce^cx, as a tool to measure how the exponential function changes with respect to variations in x. Derivatives are crucial in real-life applications, such as calculating growth rates and decay in populations or investments. We will now discuss the derivative of e^cx in detail.
The derivative of e^cx is commonly denoted as d/dx (e^cx) or (e^cx)', and its value is ce^cx. The exponential function e^cx has a well-defined derivative, indicating it is differentiable across its domain. The key concepts are mentioned below: Exponential Function: (e^cx), where c is a constant. Constant Multiple Rule: A rule for differentiating functions that are multiplied by a constant. Natural Exponential Function: e^x, where e is the base of the natural logarithm.
The derivative of e^cx can be denoted as d/dx (e^cx) or (e^cx)'. The formula we use to differentiate e^cx is: d/dx (e^cx) = ce^cx (or) (e^cx)' = ce^cx The formula applies to all x and any constant c.
We can derive the derivative of e^cx using proofs. To show this, we will use basic differentiation rules. There are several methods we use to prove this, such as: By First Principle Using the Chain Rule By First Principle The derivative of e^cx can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of e^cx using the first principle, we will consider f(x) = e^cx. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = e^cx, we write f(x + h) = e^(c(x + h)). Substituting these into equation (1), f'(x) = limₕ→₀ [e^(c(x + h)) - e^cx] / h = limₕ→₀ [e^(cx) e^(ch) - e^cx] / h = limₕ→₀ e^(cx) [e^(ch) - 1] / h Using the identity e^x ≈ 1 + x for small x, we approximate e^(ch) as 1 + ch, f'(x) = limₕ→₀ e^(cx) [ch] / h = limₕ→₀ ce^(cx) f'(x) = ce^(cx) Hence, proved. Using the Chain Rule To prove the differentiation of e^cx using the chain rule, We use the formula: e^cx = e^(u), where u = cx By the chain rule: d/dx [e^u] = e^u * du/dx So we get, d/dx (e^cx) = e^(cx) * d/dx (cx) Since d/dx (cx) = c, d/dx (e^cx) = ce^(cx)
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, consider a scenario where you are tracking the population growth rate (first derivative) and the rate at which that growth rate changes (second derivative). Higher-order derivatives help us comprehend more complex behaviors of functions like e^cx. For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative and this pattern continues. For the nth Derivative of e^cx, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change.
When c = 0, the derivative is 0 because e^0 = 1, and a constant function has a derivative of 0. When x = 0, the derivative of e^cx = ce^c(0) = c, as e^0 = 1.
Students frequently make mistakes when differentiating e^cx. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (e^2x · e^3x)
Here, we have f(x) = e^2x · e^3x. Using the property of exponents, we write: f(x) = e^(2x + 3x) = e^5x Differentiating using the rule for e^cx, f'(x) = 5e^5x Thus, the derivative of the specified function is 5e^5x.
We find the derivative of the given function by simplifying it using properties of exponents. The first step is combining exponents, then finding its derivative using the rule for exponential functions.
A company models its revenue growth using the function R(x) = e^0.1x, where x represents time in years. Find the rate of revenue growth when x = 5 years.
We have R(x) = e^0.1x (rate of revenue growth)...(1) Now, we will differentiate the equation (1) Take the derivative of e^0.1x: dR/dx = 0.1e^0.1x Given x = 5, substitute this into the derivative: dR/dx = 0.1e^(0.1 * 5) dR/dx = 0.1e^0.5 Hence, we get the rate of revenue growth at x = 5 years as 0.1e^0.5.
We find the rate of revenue growth at x = 5 years by first differentiating the revenue function. Then, substituting the given value of x, we determine the rate at that particular time.
Derive the second derivative of the function y = e^3x.
The first step is to find the first derivative, dy/dx = 3e^3x...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [3e^3x] d²y/dx² = 9e^3x Therefore, the second derivative of the function y = e^3x is 9e^3x.
We use the step-by-step process, where we start with the first derivative. We differentiate again to find the second derivative, applying the rule for exponential functions.
Prove: d/dx (e^2x) = 2e^2x.
Let’s start by applying the differentiation rule for e^cx: Consider y = e^2x To differentiate, we use the rule for exponential functions: dy/dx = 2e^2x Hence proved.
In this step-by-step process, we used the differentiation rule for exponential functions to derive the equation. The result shows that the derivative of e^2x is 2e^2x.
Solve: d/dx (e^2x/x)
To differentiate the function, we use the quotient rule: d/dx (e^2x/x) = (d/dx (e^2x) · x - e^2x · d/dx(x))/ x² We will substitute d/dx (e^2x) = 2e^2x and d/dx (x) = 1: (2e^2x · x - e^2x · 1) / x² = (2xe^2x - e^2x) / x² = e^2x(2x - 1) / x² Therefore, d/dx (e^2x/x) = e^2x(2x - 1) / x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x. Exponential Function: A mathematical function of the form e^cx, where e is Euler's number and c is a constant. Chain Rule: A rule used to differentiate composite functions. Constant Multiple Rule: A rule stating that the derivative of a constant multiplied by a function is the constant multiplied by the derivative of the function. Quotient Rule: A rule for finding the derivative of a quotient of two functions.
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